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Question

A dipole of dipole moment 20 ×10^-6 is present inside a surface.what is net outward flux


Solution

It's a very simple question.
EXPLANATION

The net flux through a surface can be found by considering a closed Gaussian surface enclosing the charges. The flux is equal to the net charge divided by ε0.

In the question, the enclosed by a Gaussian surface due to the dipole is = +q + (-q) = 0

Therefore, the flux is, ϕ = 0/ε0 = 0 

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