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Question

A disc is placed on the surface of a pond which has a refractive index 53. A source of light is placed 4m below the surface of a liquid. Find the minimum radius of a disc so that light does not come out from the disc?


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Solution

Step 1: Given data

The depth is 4mand refractive index μ=53

Step 2: Formula used

sina=1μ[μ=refractiveindex]

Step 3: Calculating the minimum radius

Firstly we will draw the diagram and then we will proceed with the solution. Here the depth is given from where the luminous object or source light is kept. And a disc is placed so that the light does not come out

Let us assume the radius of the disc is PR=x .

sina=1μ=153=35

And from the figure, we can say that, sina is nothing but perpendicular upon hypotenuse.

PROR=35

On comparing,

PR=x=3m

Hence, the minimum radius of a disc so that light does not come out from a disc is 3m.


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