CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A disc of mass $$100\ g$$ and radius $$10\ cm$$ has a projection on its circumference. The mass of projection is negligible. A $$20\ g$$ bit of putty moving tangential to the disc with a velocity of $$5\ m\ s^{-1}$$ strikes the projection and sticks to it. The angular velocity of disc is


A
14.29 rad s1
loader
B
17.3 rad s_1
loader
C
12.4 rad s_1
loader
D
9.82 rad s1
loader

Solution

The correct option is A $$14.29\ rad\ s_1$$

In this case, the angular momentum of  bit of putty about the axis of rotation = angular momentum of system of disc and bit of putty about the axis of rotation.


Let:

$$M$$ = Mass of puty

$$m$$ = Mass of disc

$$ \therefore MvR=\left( \dfrac{m{{R}^{2}}}{2}+M{{R}^{2}} \right)\omega  $$

 $$ \omega =\dfrac{MvR}{\left( \dfrac{m{{R}^{2}}}{2}+M{{R}^{2}} \right)} $$

 Putting all the values

 $$ \omega =14.298\ m/s $$


Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image