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Question

# (A) : ∫ex(logx+x−2)dx=ex(logx−1x)+c(R): ∫ex[f(x)+f′(x)]dx=exf(x)+c

A
Both A and R are true and R is the correct explanation of A
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B
Both A and R are true but R is not correct explanation of A
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C
A is true but R is false
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D
A is false but R is true.
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Solution

## The correct option is A Both A and R are true and R is the correct explanation of AA=∫ex(logx+1x2)dx∫ex[(logx−1x)+(1x2+1x)]dxIt is in the form of∫ex(f(x)+f′(x))dx=exf(x)+cSo the integral is equal to ex[logx−1x]+cA: true andR: true and R explains A.

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