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Question

A diver having a moment of inertia of 6.0 kg-m2 about an axis through its centre of mass rotates at an angular speed of 2 rad/s about this axis. If he folds his hands and feet to decrease the moment of inertia to 5.0  kg-m2, what will be the new angular speed ?


Solution

I=6kg-m2,ω=2rad/s,I2=5kg-m2

Since, external torque=0

Therefore,  I1ω1=I2ω2

          ω2=(6×2)5

=125=2.4rad/s

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