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Question

A diwali rocket is ejecting 0.05 kg of gas per second at a velocity of 400 m/sec. The accelerating force on the rocket is
  1. 20 N
  2. 22 dynes
  3. 1000 N
  4. 20 dynes


Solution

The correct option is A 20 N
F=u(dmdt)=400×0.05=20 N

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