CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A drop of liquid of diameter 2.8 mm break up into 216 identical drops. What is the approximate change in energy of bigger drop?
(Given: Surface tension of liquid, T=75 dyne/cm)

A
25π erg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
29.4π erg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
32π erg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
28π erg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 29.4π erg
Change in energy (energy required) in splitting of bigger drop to n smaller drops is,
ΔE=4πR2T(n1/31) ...(i)
Where, Radius of bigger drop
R=1.4×101 cm
n= Number of small drops
T= Surface tension
From Eq. (i) we get,
ΔE=4×π×(1.4×101)2×75(2161/31) dyne.cm
Since 1 erg=1 dyne.cm
ΔE=29.4π erg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon