Question

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more more animals in his cattle?

Answer 1

Let the number of days be $x.$

Given that he has enough food to feed $20$ animals in his cattle for $6days.$

Later on$,$ $10$ more animals were added$.$

therefore$,$ the number of days required to feed $30$ animals$.$

$20\times 6=\left(20+10\right)\times x$

$120=30\times x$

$x=\frac{120}{30}=4$

therefore$,$ the number of days $=4.$