Question

# A father is three times as old as his son. In $12$ years time, he will be twice as old as his son. Find the present ages of father and the son.

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Solution

## Let the present age of son be $x$.And the present age of father be $3x$.As given in the question,The age of son after $12$ years = $x+12$And the age of the father after $12$ years = $2\left(x+12\right)$Therefore,$\begin{array}{rcl}3x+12& =& 2\left(x+12\right)\\ & =& 3x+12=2x+24\\ & =& x=12\end{array}$Therefore,The present age of the son is $12$ years.The present age of the father is $12×3=36$ years.

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