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Question

A father is twice as old as his son. 20 years back, he was twelve times as old as his son. What are their present ages ?

A
24 years, 12 years
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B
44 years, 22 years
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C
48 years, 44 years
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D
None of these
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Solution

The correct option is B 44 years, 22 yearsLet the age of son be x years and father be 2x years.20 years back, their ages were x−20 and 2x−20As per the given condition, we get2x−20=12(x−20)⇒2x−20=12x−240⇒2x−12x=20−240⇒−10x=−220⇒x=22010⇒x=22∴ son's age is 22 years and father's age is (2×22)=44 years.

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