A fathers age is four times that of his son. After $5$ years, it will be three times that of his son. How many more years will take if fathersage is to be twice that of his son?

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Solution

Let the age of son be $x$ .
Thus, age of father is $4 x$ .
After $5$ years, their ages will be $x + 5$ and $4 x + 5$ years respectively.
As per the question, we have
$4 x + 5 = 3 (x + 5)$
$\Rightarrow 4 x + 5 = 3 x + 15$
$\Rightarrow x = 10$
Age of father will be $4 x = 4 \times 10 = 40$ years.
Thus when son is $10$ years old, father is $40$ years.

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A fathers age is four times that of his son. After 5 years, it will be three times that of his son. How many more years will take if fathersage is to be twice that of his son?

Let the age of son be x.Thus, age of father is 4x.After 5 years, their ages will be x+5 and 4x+5 years respectively.As per the question, we have4x+5=3(x+5)⇒4x+5=3x+15⇒x=10Age of father will be 4x=4×10=40 years.Thus when son is 10 years old, father is 40 years.

A fathers age is four times that of his son. After $5$ years, it will be three times that of his son. How many more years will take if fathersage is to be twice that of his son?