Question

# A fireman wants to slide down a rope. The breaking lead for the rope is $$(3/4)^{th}$$ of the weight of the man. With what minimum acceleration should the fireman slide down? (Acceleration due to gravity is $$g$$)

A
zero
B
g4
C
3g4
D
g2

Solution

## The correct option is A $$\cfrac{g}{4}$$For minimum acceleration, $$ma=mg-\dfrac{3}{4}mg$$or $$a=g(1-\dfrac{3}{4})=\dfrac{g}{4}$$Physics

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