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Question

A fireman wants to slide down a rope. The breaking lead for the rope is $$(3/4)^{th}$$ of the weight of the man. With what minimum acceleration should the fireman slide down? (Acceleration due to gravity is $$g$$)


A
zero
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B
g4
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C
3g4
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D
g2
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Solution

The correct option is A $$\cfrac{g}{4}$$
For minimum acceleration, $$ma=mg-\dfrac{3}{4}mg$$
or $$a=g(1-\dfrac{3}{4})=\dfrac{g}{4}$$

Physics

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