Question

A first order reaction has a rate constant $$1.15\times 10^{-3}s^{-1}$$. How long will $$5\ g$$ of this reactant take to reduce to $$3\ g$$?

A
444 s
B
400 s
C
528 s
D
669 s

Solution

The correct option is A $$444\ s$$$$t = \dfrac {2.303}{k}\log \dfrac {[R_{0}]}{[R]} = \dfrac {2.303}{1.15\times 10^{-3}} \log\left( \dfrac {5}{3}\right)$$$$= 2.00\times 10^{3} \log (1.667)$$$$= 2\times 10^{3} \times 0.2219 = 444\ s$$.Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More