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Question

A fish is swimming in a river at a depth of 20 cm from the surface of the water. The refractive index of water is 4/3. An eagle flying above the water will see the fish at a depth of ___cm


Solution

In the given situation, 

Refractive index of water, μwater  = 43

Refractive index of water =  Real  depthApparent  depth

Therefore, apparent depth =  20×34 = 15 cm

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