A flag pole 18m high casts a shadow 9.6m long. Find the distance of the top of the pole from the far end of the shadow.
Let's find the length of LN in the figure.
Let MN=18m be the flag pole and its shadow be LM=9.6m
The distance of the top of the pole,N from the far end, Lof the shadow is LN.
From right-angled ∆LMN,
On applying Pythagoras theorem we obtain
Hence, the required distance is 20.4m
A 5 m 60 cm high
vertical pole casts a shadow 3 m 20 cm long. Find at the same time −
(i) the length of the
shadow cast by another pole 10 m 50 cm high
(ii) the height of a
pole which casts a shadow 5 m long.