Question

# A flip coil consists of N turns of circular coils which lie in a uniform magnetic field. Plane of the coils is perpendicular to the magnetic field as shown in figure. The coil is connected to a current integrator which measures the total charge passing through it. The coil is turned through 180o about the diameter. The charge passing through the coil is

A
NBAR
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B
3NBA2R
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C
NBA2R
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D
2NBAR
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Solution

## The correct option is D 2NBARThe emf induced in the coil is given by dϕdt.The current passing through the circuit thus becomes i=dϕdtR.Hence the total charge that passed through the current integrator=∫idt=1R∫dϕdtdt=ΔϕR=NBA−(−NBA)R=2NBAR

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