A floor measuring 2 m by 1-5 m is to be covered with tiles measuring 25 cm- 25 cm- Find the number of tiles required to cover the floor and the cost of the tiles at Rs- 420 per dozen-

The correct option is C 48, Rs. 1680 Number of tiles required = Area of rectangular floorArea of each tile = 200× 15025× 25 = 48 Cost of 12 ...

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Standard VI

Mathematics

Area of Square

A floor measu...

Question

A floor measuring $2 m$ by $1.5 m$ is to be covered with tiles measuring $25 c m \times 25 c m$ . Find the number of tiles required to cover the floor and the cost of the tiles at $R s . 420$ per dozen.

24, R s . 1380

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48, R s . 1680

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48, R s . 1285

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24, R s . 2000

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Solution

The correct option is C $48, R s . 1680$
Number of tiles required $= \frac{Area of rectangular floor}{Area of each tile}$
$= \frac{200 \times 150}{25 \times 25} = 48$
Cost of $12 t i l e s = R s . 420$
So, cost of $1 t i l e = R s . \frac{420}{12} = R s . 35$
Cost of $48 t i l e s = R s (35 \times 48) = R s . 1680$ .

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A floor measuring 2 m by 1.5 m is to be covered with tiles measuring 25 cm×25 cm. Find the number of tiles required to cover the floor and the cost of the tiles at Rs.420 per dozen.

The correct option is C 48,Rs.1680Number of tiles required =Area of rectangular floorArea of each tile=200×15025×25=48Cost of 12 tiles=Rs.420So, cost of 1 tile=Rs.42012=Rs.35Cost of 48 tiles=Rs(35×48)=Rs.1680.

A floor measuring $2 m$ by $1.5 m$ is to be covered with tiles measuring $25 c m \times 25 c m$ . Find the number of tiles required to cover the floor and the cost of the tiles at $R s . 420$ per dozen.