Question

A fly wheel rotating at 600 rev/min is brought under uniform deceleration and stopped after 2 min, then what is the angular deceleration in rad/$se{c}^2$?

• A. $\frac{\pi }{6}$
• B. 10 $\pi$
• C. 1/12
• D. 300

Answer 1

The correct option is A $\frac{\pi }{6}$

The correct option is A.

Given,

Angular revolution is $\omega =600r.p.m=600\times \frac{\pi }{60}=20\pi$

Here, ${\omega }_0=0$

$t=12s$

The angular deceleration is:

$\frac{{\omega }_0-\omega }{t}$

$\frac{0-20\pi }{6}=\frac{\pi }{6}$