A force $40 k g f$ produces a moment of $120 k g f m$ about a given axis of rotation. Find the minimum distance between the line of action of the force and the axis of rotation?

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Solution

Step 1: Given data
Force $= 40 k g f = 40 N$
Moment of force $= 120 k g f m = 120 N m$
Step 2: Formula
Moment of force or Torque $= F o r c e \times P e r p e n d i c u l a r d i s \tan c e$
Step 3: Calculating perpendicular distance or distance between the line of action of the force and the axis of rotation
$120 k g f m = 40 k g f \times P e r p e n d i c u l a r d i s \tan c e$
Perpendicular distance $= \frac{120 k g f m}{40 k g f} = 3 m$
Hence, the minimum distance between the line of action of the force and the axis of rotation is $3 m .$

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