Question

A force acts for $10s$ on a body of mass $10kg$ after which the force ceases and the body moves $50m$ in the next $5s$. Find the magnitude of the force.

Answer 1

Let the body starts from rest.

$\therefore u=0$

Final velocity = distance / time = 50/5 = 10 m/s

Now, using equation of motion, v = u + at

$a=\frac{v-u}{t}=\frac{10-0}{10}=1m{s}^{-2}$

Force = F= ma = $10kg\times 1m{s}^{-2}$ = 10 N