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Question

A force F doubles the length of wire of cross-section a. The Young modulus of wire is

A
Fa
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B
F3a
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C
F2a
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D
F4a
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Solution

The correct option is D F2a
As youngsters modulus is given as,
Y=f/a. L/ΔL
From above we can conclude that
Y=2Y
That is youngs modulus becomes 2 times to its original value.
Hence,
option (C) is correct answer.

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