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Question

A force of 10 N acting on a body at an angle of 600 with the horizontal direction displaces the body through a distance of 2 m along the surface of a floor. Calculate the work done. Now let the force or pull acting on the body makes an angle of 300 with the horizontal. What is the value of the force to displace the body through 2m along the surface of the floor?

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Solution

Work done in fruit case =F.S.cosθ=10×2×cos6010J
Work done in second case is same as 10J=FScosθF×2×cos30=10F=103N

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