Question

A force of $16N$ is applied on a block of $4kg$ with $\mu =0.6$. Then the force of friction acting on the block is

• A. $20N$
• B. $24N$
• C. $16N$
• D. $0N$

Answer 1

Answer: (B)

$24N$

$Given$ :- Mass of block ( $m$ ) = 4 Kg

Coefficient of friction ( $\mu$ ) = 0.6

Acceleration due to gravity $\left(g\right)$ = 10 ${m/s}^2$

Applied Force $\left(F\right)$ = 16 N

$ToFind$ :- frictional force $\left(f\right)$

$Solution$ :- Since , the block is not moving vertically

$\therefore$ $N=mg=4g$

Now we know , $f_{max}=\mu N$

$\therefore$ $f_{max}=0.6\times 40⟹\underset{–}{24N}$

Hence , $\underset{–}{OptionB\left(24N\right)iscorrect.}$