Question

# A force of $600$ newtons will compress a spring $0.5$ metres. What is the spring constant of the spring?

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Solution

## Step 1: Given dataForce (f) = $600N$Displacement of the spring (x) = $0.5m$Step 2: Formula usedAccording to Hooke's law, $F=kx$, where F is the force applied, k is the spring constant and x is the displacement of the spring.Step 3: Calculate spring constantWe, know that $F=kx$, thus on re-arranging, we get:$k=\frac{F}{x}$On substituting the given values in the equation, we get:$k=\frac{600}{0.5}\phantom{\rule{0ex}{0ex}}=1200N/m$Thus, the spring constant of the spring will be $1200N/m$.

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