Question

# A force of $7N$ acts on an object. The displacement is, say $8m$, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case?

Open in App
Solution

## Step 1: Given dataForce acting on the body (F) = $7N$Displacement of the body (S) = $8m$Step 2: Formula used$W=FS\mathrm{cos}\theta$, where W is the work done, F is the force acting on the body, S is its displacement and $\theta$ is the angle between the direction of force and the displacement vector.Step 3: Calculate work doneSince the body is displaced in the direction of the applied force, $\theta =0$. Now, on substituting the given values in the formula, we get: $W=7·8·\mathrm{cos}\left(0°\right)\phantom{\rule{0ex}{0ex}}W=7·8·1\phantom{\rule{0ex}{0ex}}W=56J$Thus, the work done in this case will be $56J$.

Suggest Corrections
22
Explore more