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Question

A force of 750 N is applied to a block of mass 102 kg to prevent it from sliding on a plane with an inclination angle 30o with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block is
 


  1. 750 N

  2. 500 N

  3. 345 N

  4. 250 N


Solution

The correct option is D

250 N



Net force along the palne
=P-mg~sin\theta=750-500=250~N\)
Limiting friction=(F_1=\mu_1R=\mu_1~mg~cos\theta\)
=0.4×102×9.8×cos 30=346 N
As net external force is less than limiting friction therefore friction on the body will be 250 N.

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