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A force of F=3^i+4^j is acting on a box at pointA whose position vector with respect to origin is <2,3>.Work done in displacing the particle fromA to B whose position vector with respect to origin is <5,6> will be ....... units


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Solution

The box has to be displaced from A to B. So the vector AB will be the displacement vector of the box.OA=[23]OB=[56],where O is the originAB=OBOA=[56][23]=[33]=3i+3j.Now the work done will F.AB=(3^i+4^j).(3^i+3^j)=9+0+0+12=21 units


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