A force produces an acceleration of $4 m / s^{2}$ in a body of mass $m_{1}$ and the same force produces an acceleration of $6 m s^{- 2}$ in another body of mass $m_{2}$ . If the same force is applied to ( $m_{1} + m_{2}$ ), then the acceleration will be :

10

m / s^{2}

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2

m / s^{2}

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2.4

m / s^{2}

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5.4

m / s^{2}

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Solution

The correct option is C $2.4$ $m / s^{2}$
As we know that $F O R C E$ = $M A S S$ $\times$ $A C C E L E R A T I O N$
SO $F_{1}$ = $m_{1}$ $\times 4$
$F_{2}$ = $m_{2}$ $\times 6$
now for combined system total acceleration will be $" a "= \frac{F}{m_{1} + m_{2}}$
$m_{1}$ = $\frac{F}{4}$
$m_{2}$ = $\frac{F}{6}$
so put the value of $m_{1}$ and $m_{2}$ we find
$a_{t o t a l} = 2.4 m / s^{2}$

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A force produces an acceleration of 4m/s2 in a body of mass m1 and the same force produces an acceleration of 6ms−2 in another body of mass m2. If the same force is applied to (m1+m2), then the acceleration will be :

The correct option is C 2.4 m/s2As we know that FORCE=MASS×ACCELERATIONSO F1=m1×4F2=m2×6now for combined system total acceleration will be "a"=Fm1+m2m1=F4m2=F6so put the value of m1 and m2 we findatotal=2.4m/s2

A force produces an acceleration of $4 m / s^{2}$ in a body of mass $m_{1}$ and the same force produces an acceleration of $6 m s^{- 2}$ in another body of mass $m_{2}$ . If the same force is applied to ( $m_{1} + m_{2}$ ), then the acceleration will be :