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Standard XII

Chemistry

System, Surroundings, Intensive, Extensive Properties

A force F⃗=...

Question

A force $\to F = 2^i + 3^j - 4^k$ $N$ , acts on a particle which is constrained to move in the X-Y plane along the line $x = y$ . If the particle moves $5 \sqrt{2}$ m, the work done by force in joule is:

25 \sqrt{2}

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5 \sqrt{58}

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Solution

The correct option is B 25
$\to S = \frac{5 \sqrt{2}}{\sqrt{2}} (^i +^j)$
$\to F = (2, 3, - 4)$
$W . D = \to F . \to S$ $= 10 + 15 = 25$

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A force →F=2^i+3^j−4^k N, acts on a particle which is constrained to move in the X-Y plane along the line x=y. If the particle moves 5√2 m, the work done by force in joule is:

The correct option is B 25→S=5√2√2(^i+^j)→F=(2,3,−4)W.D=→F.→S =10+15=25

A force $\to F = 2^i + 3^j - 4^k$ $N$ , acts on a particle which is constrained to move in the X-Y plane along the line $x = y$ . If the particle moves $5 \sqrt{2}$ m, the work done by force in joule is:

The correct option is B 25
$\to S = \frac{5 \sqrt{2}}{\sqrt{2}} (^i +^j)$
$\to F = (2, 3, - 4)$
$W . D = \to F . \to S$ $= 10 + 15 = 25$