Question

# A force $$\vec{F}=\hat{i}+4\hat{j}$$ acts on the block shown. The force of friction acting on the block is

A
^i
B
1.8^i
C
2.4^i
D
3^i

Solution

## The correct option is A $$\displaystyle -\hat{i}$$Normal reaction is given by:$$N = mg - F_y = 10-4 = 6N$$Maximum frictional force on the block is:$$F_r = \mu N = 0.3 \times 6 = 1.8 N$$Since $$F_x = 1 < F_r$$, block does not move.$$F_r = 1 N$$ opposite to the direction of $$F_x$$or $$F_r = - \hat i$$Physics

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