A fruit is dropped from a height of 20 m. Find the velocity with which it would hit the ground.

40 m s^{- 1}

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50 m s^{- 1}

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20 m s^{- 1}

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30 m s^{- 1}

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Solution

The correct option is C $20 m s^{- 1}$
Given:
Displacement, $s = - 20 m$
Initial velocity, $u = 0$

Acceleration due to gravity, $g \approx - 10 m / s^{2}$
Upward direction is taken as positive.

From the third equation of motion,
$v^{2} = u^{2} + 2 a s$
$v^{2} = 0^{2} + 2 \times (- 10) \times - 20$
$v = 20 m s^{- 1}$

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A fruit is dropped from a height of 20 m. Find the velocity with which it would hit the ground.

The correct option is C 20 ms−1Given: Displacement, s=−20 m Initial velocity, u=0 Acceleration due to gravity, g≈−10 m/s2 Upward direction is taken as positive. From the third equation of motion, v2=u2+2as v2=02+2×(−10)×−20 v=20 ms−1