Question

# A fundamental particle of mass m and charge +e is projected, towards a heavy particle of charge Ze (when Z>0) with velocity v, distance of nearest approach is:-

A
Ze22πε0mv2
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B
Ze4πε0mv2
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C
Ze28πε0mv2
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D
Ze8πε0mv2
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Solution

## The correct option is A Ze22πε0mv2The potential energy of a particle of mass m, charge e and particle of charge Ze is, U=14πεZe2r {U=Kq1q2r} During the process, when the particle of charge e, approaches charge Ze, kinetic energy is converted into potential energy. ⇒12mv2=14πε0Ze2r Distance of closest approach is, r=Ze22πε0mv2

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