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Question

A galvanometer has a resistance of $$25 \ ohm$$ and a maximum of $$0.01\ A$$ current can be passed through it. In order to change it into an ammeter of range $$10\ A$$, the shunt resistance required is


A
5/999 ohm
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B
10/999 ohm
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C
20/999 ohm
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D
25/999 ohm
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Solution

The correct option is D $$25/999\ ohm$$
Given a galvanometric coil
Resistance on  galvanometer = $$ 25 \Omega$$
Current on the galvanometer = $$0.01A$$
Ammmeter range = $$10 A$$
From formula we know that, 

$$i_g=i\dfrac{S}{G+S} \Rightarrow 0.01 =10 \dfrac{S}{25+S}$$

$$\Rightarrow 1000 S=25+S \Rightarrow S=\dfrac{25}{999} \Omega$$

Physics
NCERT
Standard XII

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