Question

# A galvanometer has a resistance of $$25 \ ohm$$ and a maximum of $$0.01\ A$$ current can be passed through it. In order to change it into an ammeter of range $$10\ A$$, the shunt resistance required is

A
5/999 ohm
B
10/999 ohm
C
20/999 ohm
D
25/999 ohm

Solution

## The correct option is D $$25/999\ ohm$$Given a galvanometric coilResistance on  galvanometer = $$25 \Omega$$Current on the galvanometer = $$0.01A$$Ammmeter range = $$10 A$$From formula we know that, $$i_g=i\dfrac{S}{G+S} \Rightarrow 0.01 =10 \dfrac{S}{25+S}$$$$\Rightarrow 1000 S=25+S \Rightarrow S=\dfrac{25}{999} \Omega$$PhysicsNCERTStandard XII

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