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Question

A galvanometer has a resistance of 25 ohm and a maximum of 0.01 A current can be passed through it. In order to change it into an ammeter of range 10 A, the shunt resistance required is

A
5/999 ohm
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B
10/999 ohm
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C
20/999 ohm
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D
25/999 ohm
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Solution

The correct option is D 25/999 ohm
Given a galvanometric coil
Resistance on galvanometer = 25Ω
Current on the galvanometer = 0.01A
Ammmeter range = 10A
From formula we know that,

ig=iSG+S0.01=10S25+S

1000S=25+SS=25999Ω

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