Question

# A galvanometer having internal resistance $$10\ \Omega$$ requires $$0.01 \ A$$ for a full scale deflection. To convert this galvanometer to a voltmeter of full-scale deflection at $$120\ V$$, we need to connect a resistance of:

A
11990 Ω in series
B
11990 Ω in parallel
C
12010 Ω in series
D
12010 Ω in parallel

Solution

## The correct option is B $$11990\ \Omega$$ in seriesGiven :           $$G = 10 \Omega$$               $$I_G = 0.01 A$$              $$V = 120$$ voltLet the resistance to be connected in series be $$R$$$$\therefore$$            $$V = I_G (G+R)$$$$120 = 0.01 (10 + R)$$$$\implies$$  $$R = 11990$$ $$\Omega$$Physics

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