Question

A game of chance consist of spinning an arrow, which comes to rest pointing at one of the numbers $1,2,3,4,5,6,7,8$ and these are equally likely outcomes, Find the probability that the arrows will point at any factor of $8$.

Answer 1

Given that,

Number of events $=1,2,3,4,5,6,7,8$

Total numbers $n\left(S\right)=8$

Factor of $8=1,2,4$ and $8$

Number of factor $n\left(E\right)=4$

Therefore,

$Probability=\frac{n\left(E\right)}{n\left(S\right)}$ $=\frac{4}{8}$

$Probability=\frac{1}{2}$.