A garden lizard accelerates from $2 m s^{- 1}$ to $10 m s^{- 1}$ in $4 s e c o n d s$ . What is the lizard’s average acceleration?

2 m s^{- 2}

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- 2 m s^{- 2}

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3 m s^{- 2}

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- 3 m s^{- 2}

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Solution

The correct option is A $2 m s^{- 2}$
Accelaration = Rate of change of speed
$\frac{f i n a l v e l o c i t y - i n i t i a l v e l o c i t y}{T i m e}$
$\frac{10 - 2}{4} = 2 m s^{- 2}$

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Similar questions

40 m s^{- 1}

20 s

An object at rest starts moving and attains a velocity of $10 m s^{- 1}$ after 5 s. What is the acceleration?

2 m s^{- 2}

x - y

v_{x} = 3 {ms}^{- 1}, v_{y} = 4 {ms}^{- 1}, a_{x} = 2 {ms}^{- 2}

a_{y} = 1 {ms}^{- 2}

4 {ms}^{- 1}

20 {ms}^{- 1}

4 s

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