Question

A gardener pushes a lawn roller through a distance of 100m with a force of 50N . Calculate the wages if he is to be paid Re:1 for

25 J of work It is given that the applied force is inclined 60^oto the direction of motion .

Answer 1

$$\begin{gathered} \mathrm{Work}\mathrm{done}=\mathrm{f}\times \mathrm{s}\mathrm{cos\theta } \\ \mathrm{\theta }\mathrm{is}\mathrm{the}\mathrm{angle}\mathrm{between}\mathrm{direction}\mathrm{of}\mathrm{force}\mathrm{and}\mathrm{distance}. \\ \mathrm{Work}\mathrm{done}=50\times 100\cos 60° \\ =5000\times \frac{1}{2}=2500\mathrm{J}\mathrm{for}25\mathrm{J}\mathrm{of}\mathrm{work}\mathrm{he}\mathrm{get}1\mathrm{rupee}\mathrm{for}2500\mathrm{J}\mathrm{of}\mathrm{work}\mathrm{he}\mathrm{will}\mathrm{get}=\frac{2500}{25}=\mathrm{Rs}100 \end{gathered}$$