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Question

A garrison of 120 man has provision for 30 days. At the end of 5 days:5 more men joined them. How many days can they sustain on the remaining provision?


Solution

We know that no. of days is inversely proportional to the provision for men.
So for 120 men the provision would last for 30 days (given)
Therefore, the provision for 1 men would sustain for 120×30=3600 days
Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days.
120×30=120×5+125×x
(120×30)(120×5)=125x
120(305)=125x
120×25=125x
120=5x
x=1205
x=24
So the provision would remain for more 24 days.

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