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Question

A gas absorbs a photon of 355nm and emits two wavelength .If one of the emissher ions is at 680nm,the other is at:

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Solution

According to law of conservation of energy.
Energy of photon = Total energy of emissher ions
hcλphoton=hcλemissher+hcλotherion
1λphoton=1λem+1λOion
13351680=1λOion
λotherion=647.50 nm

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