Question

A gas cylinder has walls that can bear a maximum pressure of $1.0\times {10}^{6}Pa.$ It contains a gas at $8.0\times {10}^5$ Pa and $300$ K. The cylinder is steadily heated. Neglecting any change in the volume, calculate the temperature at which the cylinder will break.

Answer 1

$P_1=8.0\times {10}^{5}Pa$

Since, $V_1=V_2=V$

$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}\Rightarrow \frac{8\times {10}^5\times V}{300}=\frac{1\times {10}^6\times V}{T_2}\Rightarrow T_2=\frac{1\times {10}^6\times 300}{8\times {10}^5}={375}^{\circ }K$