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Question

A gas cylinder has walls that can bear a maximum pressure of 1.0×106 Pa. It contains a gas at 8.0×105 Pa and 300 K. The cylinder is steadily heated. Neglecting any change in the volume, calculate the temperature at which the cylinder will break.


Solution

Given 

Pmax=1.0×106 Pa, 

P0=8.0×105 Pa, 

T0 = 300 K

Volume is constant (Given)
So Gas law, 

P1V1T1=P2V2T2     (V1=V2)

P1T1=P2T2

or T2=Pmax×T0P0

= 10×106×3008.0×105

= 375 K

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