CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A gas has the thermodynamic variables $$P, V$$ and $$T$$ and is in container $$A$$. Another gas in container $$B$$ has variables $$2P, V/4$$ and $$2T$$. Find the ratio of molecules in container $$A$$ and $$B$$.


Solution

$$PV = nRT$$
$$\therefore\cfrac{PV}{T} = nR$$
$$\therefore\cfrac{P_AV_A}{T_A} = n_AR$$
And , $$\cfrac{P_AV_A}{T_A} =$$$$\cfrac{PV}{T} $$
and, $$\cfrac{P_BV_B}{T_B} =$$$$\cfrac{2PV}{2T \times 4} $$$$=\cfrac{PV}{4T} $$
$$\therefore\cfrac{n_A}{n_B} = (\cfrac{P_AV_A}{T_A})/ $$$$(\cfrac{P_BV_B}{T_B} ) = 4$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image