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Question

A gas initially at 0 °C is heated so that its pressure and volume are both doubled. What will be its final temperature?​

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Solution

According to Boyle's law and Charle's law, we get the gas equation.​
P1V1T1= P2V2T2
Given, V2= 2V1 ; P2= 2P1; T1 = (0 + 273) K , T2 = ?
P1V1273= 2P1 X 2V1T2;or T2= 4 x 273 = 1092 K​
Final temperature = (1092 - 273) K = 819 °C

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