Question

# A gas under constant pressure of $$4.5\times 10^{5} Pa$$ when subjected to $$800 \ KJ$$ of heat, changes the volume from $$0.5\ m^{3}to\ 2.0\ m^{3}$$. The change in the internal energy of the gas:

A
6.75×105J
B
5.25×105J
C
3.25×105J
D
1.25×105J

Solution

## The correct option is D $$1.25\times 10^{5} J$$Given data,$$P=4.5\times 10^{5}Pa$$$$dQ=800kJ$$$$V_{1}=0.5m^{3}$$$$V_{2}=2m^{3}$$$$dW=P(V_{2}-V_{1})=4.5\times10^{5}(2\times0.5)$$$$=6.75\times 10^{5}J$$Change in internal energy $$dU=dQ-dW$$$$U=800\times 10^3-675\times 10^3$$$$=125\times 10^3J$$$$=1.25\times 10^5 J$$Option D.Physics

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