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Question

A gaseous mixture containing CO, CH4 and N2 gas has total volume of 40 mL. This mixture is exploded with excess of oxygen, on cooling 30 mL of contraction is observed and when this mixture is treated with aqueous KOH a further contraction of 30 mL is observed. Find the composition of the mixture in mL.

A
CO=20,CH4=10,N2=10
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B
CO=15,CH4=15,N2=10
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C
CO=10,CH4=15,N2=15
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D
CO=20,CH4=15,N2=5
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Solution

The correct option is B CO=15,CH4=15,N2=10
Let volume of CO, CH4, N2 be x, y, z mL respectively.
On explosion with excess of O2 the following reaction takes place:
COx mL(g)+12O2(g) CO2x mL(g)
CH4y mL(g)+2O2(g) CO2y mL(g)+2H2O (g)2y mL
N2 remains unreacted.
On cooling H2O gas liquifies hence, volume reduction of 30 mL is observed.
2y = 30 y = 15
Volume of CH4 = 15 mL
But volume of CO2 = (x + y)
As we know CO2 is absorbed on KOH and volume reduction of 30 mL is observed.
(x + y) = 30 x = 15 mL
Volume of CO = 15 mL
x + y+ z = 40 mL z = 10 mL
Volume of N2 = 10 mL


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