Question

A gaseous mixture of three gases $A,B$ and $C$ has pressures of 10 $atm$. The total number of moles of all the gases is 10. If the partial pressures of $A$ and $B$ are 3.0 and 1.0 $atm$ respectively and if $C$ has a mol. wt. of 2.0. What is the weight of $C$ in grams present in the mixture?

• A. 6
• B. 3
• C. 12
• D. 8

Answer 1

Answer: (C)

12

Total pressure of the gas= 10

We know, $P_x=P_{total}\times X_x$

$3=10\times X_a$

$1=10\times X_b$

$6=10\times X_c$

$X_a=0.3,X_b=0.1,X_c=0.6$

Then, $n_c=6$

$\frac{w}{2}=6$

So, $w_c=12$