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Question

# A generator is connected through a 20 MVA, 13.8/138 kV step down transformer, to a transmission line. At the receiving end of the line a load is supplied through a step down transformer of 10 MVA. 138/69 kV rating. A 0.72 p.u. load, evaluated on load side transformer ratings as base values, is supplied from the above system. For system base values of 10 MVA and 69 kV in load circuit, the value of the load (in per unit) in generator circuit will be.

A
36
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B
1.44
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C
0.72
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D
0.18
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Solution

## The correct option is A 36Base values on load circuit, (MVA)B=10MVA and (kV)B=69kV Base impedance=69210=476.1 Values of load in ohm=ZL = Value of load in p.u.× Base impedance ⇒ZL=0.72×476.1=342.8Ω Base values in generator circuit, (MVA)B=20MVA (kV)B=13.8kV Base impedance =ZB=(kV)2B(MVA)B=13.8220 ⇒ZB=9.522Ω ZLZB=324.89.522=36p.u.

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