    Question

# A girl weighing 50 kg is standing on a pencil heels. Each having an area of cross-section 1cm2. An elephant weighing 200 kg and foot area of cross-section of 250 cm2 standing on the floor. Which of the two exerts more pressure on the floor? (Given acceleration due to gravity = 10 m/s2)

Open in App
Solution

## Weight of the girl = 50 kg (Given) Area of the cross-section = 1 cm2 (Given) $\mathrm{P}=\frac{\mathrm{Force}}{\mathrm{Area}}$ Force = Weight of the body = 50 kg $\mathrm{Pressure},\mathrm{P}=\frac{50\mathrm{kg}}{1{\mathrm{cm}}^{-2}}$ 1 cm = $\frac{1}{100}$ $\therefore \mathrm{P}=\frac{50}{\frac{1}{10000}}$ P = 500000 Nm–2 Weight of the elephant, W = 200 kg Area of the cross-section of foot A = 250 cm2 A = 0.0250 m2 Pressure exerted by the elephant on land: $\mathrm{P}=\frac{\mathrm{Force}}{\mathrm{Area}}=\frac{200}{0.0250}=\frac{2000000}{250}\phantom{\rule{0ex}{0ex}}\mathrm{P}=8000{\mathrm{Nm}}^{-2}$  Suggest Corrections  1      Similar questions  Related Videos   Thrust and Pressure
PHYSICS
Watch in App  Explore more