A girl weighing 50 kgf wears sandals of pencil heel of area of cross section 1 $c m^{2}$ , stands on a floor. An elephant weighing 2000 kgf stands on foot each of area of cross section 25 $c m^{2}$ , on the floor. Compare the pressure exerted by them.

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Solution

Given,
Weight of girl $F = 50 k g f = 500 N$
Heel of area of cross-section $= 1 c m^{2}$
Area of cross-section of both heels $= 1 \times 2 = 2 c m^{2}$
Weighing of elephant $= 2000 k g f = 20000 N$
Area of cross-section of each foot $= 25 c m^{2}$
Area of cross-section all foots $= 25 \times 4 = 100 c m^{2}$

Pressure exerted by girl $P_{g i r l} = \frac{F_{g i r l}}{A r e a} = \frac{500}{2} = 250 N / c m^{2}$ ......... (1)

Pressure exerted by elephant $P_{e l e p h a n t} = \frac{F_{e l e p h a n t}}{A r e a} = \frac{20000}{100} = 200 N / c m^{2}$ ........(2)

On comparing above two-equation, Girl will apply more pressure on the ground.

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