A goldsmith can choose between 3 metals A, B or C to make an artefact. He has 2 sheets of A, 3 sheets of B, 1 sheet of C and selected 1 sheet at random. What is the probability that he chooses C?

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Solution

The correct option is C
1

The total number of sheets = 6

Number of sheets of C = 1

$P (C) = \frac{Number of favourable outcomes}{Total number of possible outcomes}$

where P(C) = Probability of getting metal C

= $\frac{Number of sheets of C}{Total number of sheets}$

= $\frac{1}{6}$ .

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A goldsmith can choose between 3 metals A, B or C to make an artefact. He has 2 sheets of A, 3 sheets of B, 1 sheet of C and selected 1 sheet at random. What is the probability that he chooses C?

The correct option is C 1 The total number of sheets = 6 Number of sheets of C = 1 P(C) = Number of favourable outcomesTotal number of possible outcomes where P(C) = Probability of getting metal C =Number of sheets of CTotal number of sheets = 16.

The correct option is C
1

The total number of sheets = 6

Number of sheets of C = 1

$P (C) = \frac{Number of favourable outcomes}{Total number of possible outcomes}$

where P(C) = Probability of getting metal C

= $\frac{Number of sheets of C}{Total number of sheets}$

= $\frac{1}{6}$ .